SIN 2MC S AM AC MACAMC22 2 2

Question

1. . .sin 2MC S AM AC MACAMC22 2 2. . .cos 2 13BC  AB AC  AB AC BAC 3 6 13MB BC 5 52 4 13MC BC Cách khác :S S SABC AMB AMC1 1 1  . . .sin . . .sin . . .sin  2 AB AC BAC 2 AB AM BAM 2 AM AC MAC0 0 0.2 3.4.sin150 .2 3. .sin120 . .4.sin 302 2 AM 2 AM1 1 1 3 1 1 4 3.2 3.4. .2 3. . . .4.    2 2 2 AM 2 2 AM 2 AM 52 2 6 13

Accepted Answer

1. . .sin 2MC S AM AC MACAMC22 2 2. . .cos 2 13BC  AB AC  AB AC BAC 3 6 13MB BC 5 52 4 13MC BC Cách khác :S S SABC AMB AMC1 1 1  . . .sin . . .sin . . .sin  2 AB AC BAC 2 AB AM BAM 2 AM AC MAC0 0 0.2 3.4.sin150 .2 3. .sin120 . .4.sin 302 2 AM 2 AM1 1 1 3 1 1 4 3.2 3.4. .2 3. . . .4.    2 2 2 AM 2 2 AM 2 AM 52 2 6 13

SIN 2MC S AM AC MACAMC22 2 2

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