GIA'I PHU.O.NG TRNH
102)
Gia'i phu.o.ng trnh:
2y” + 5y0
= 29xsinxHD gia’i:Phu.o.ng trnh da.c tru.ng:
2λ2
+ 5λ= 0 ⇔λ1
= 0, λ2
=−525xNghi^e.m t^o'ng quat cu'a phu.o.ng trnh thu^an nh^at
y=C1
+C2
e−
20
= 29xsinxHD gia’i:2
+ 5λ= 0 ⇔λ1
= 0, λ2
=−525x1
+C2
e−
2