GIA'I PHU.O.NG TRNH
3)
Gia'i phu.o.ng trnh:
a(xy0
+ 2y) = xyy0
HD gia’i: a(xy0
+ 2y) = xyy0
⇒x(a−y)y0
=−2ayN^eu
y6= 0, ta co phu.o.ng trnh tu.o.ng du.o.ng vo.i
a−yy dy =−2ax dx⇔x2a
ya
e−y
=C0
+ 2y) = xyy0
HD gia’i: a(xy0
+ 2y) = xyy0
⇒x(a−y)y0
=−2ay2a
ya
e−y
=C