GIA'I PHU.O.NG TRNH

1)

Gia'i phu.o.ng trnh:

^2xy

⁰

^{y” =y}

⁰²

⁻¹HD gia’i:

D - a.t

^y

⁰

^{=p: 2xpp}

⁰

^=p

²

⁻¹

Vo.i

^x(p

²

^{−1)6= 0}

ta co:

^2pdpC

₁

x+ 1p

²

−1 = dxx ⇔p

²

−1 =C

₁

⇔p=±√p= dyC

₁

+ 1 ⇒y= 2dx =√3C

₁

(C

₁

x+ 1)

³

²

+C

₂