GIA'I PHU.O.NG TRNH
108)
Gia'i phu.o.ng trnh:
y” +y0
=xe−x
HD gia’i:Phu.o.ng trnh da.c tru.ng:
λ2
+λ= 0⇔λ1
= 0; λ2
=−1Nghi^e.m t^o'ng quat cu'a phu.o.ng trnh thu^an nh^at:
y=C1
+C2
e−x
Tm nghi^e.m ri^eng da.ng:
y=xe−x
(Ax+B)K^et qua':
y=C1
+C2
e−x
−(x2
2 +x)e−x