GIA'I PHU.O.NG TRNH
23)
Gia'i phu.o.ng trnh:
(y02
−1)x2
y2
+y0
(x4
−y4
) = 0HD gia’i:La phu.o.ng trnh da'ng c^ap nhu.ng gia'i kha phu.c ta.p.
Xem phu.o.ng trnh b^a.c hai d^oi vo.i
y0
:
4= (x4
+y4
)2
⇒y1
0
= y2
x2
; y2
0
=−x2
y2
.Tu. do co hai ho. nghi^e.m t^o'ng quat:
y = C x1
x+ 1; x3
+y3
=C2