GIA'I PHU.O.NG TRNH

23)

Gia'i phu.o.ng trnh:

(y

02

1)x

2

y

2

+y

0

(x

4

y

4

) = 0HD gia’i:

La phu.o.ng trnh da'ng c^ap nhu.ng gia'i kha phu.c ta.p.

Xem phu.o.ng trnh b^a.c hai d^oi vo.i

y

0

:

4= (x

4

+y

4

)

2

y

1

0

= y

2

x

2

; y

2

0

=−x

2

y

2

.

Tu. do co hai ho. nghi^e.m t^o'ng quat:

y = C x

1

x+ 1; x

3

+y

3

=C

2