GIA'I PHU.O.NG TRNH
22)
Gia'i phu.o.ng trnh:
(x−ycosyx)dx+xcosyxdy= 0HD gia’i:D - a.t
yx =z ⇒y0
=z0
x+zphu.o.ng trnh du.o..c du.a v^e da.ng:
Zxcosz.z0
+ 1 = 0⇔coszdz =−dxx +C ⇔sinz=−ln|x|+C0
=z0
x+z0
+ 1 = 0⇔coszdz =−dxx +C ⇔sinz=−ln|x|+C