GIA'I PHU.O.NG TRNH
103)
Gia'i phu.o.ng trnh:
y”−2y0
+ 5y=xsin 3xHD gia’i:Phu.o.ng trnh da.c tru.ng:
λ2
−2λ+ 5 = 0⇔λ1
= 1−2i;λ2
= 1 + 2iNTQ cu'a phu.o.ng trnh thu^an nh^at:
y =ex
(C1
cos 2x+C2
sin 2x)0
+ 5y=xsin 3xHD gia’i:2
−2λ+ 5 = 0⇔λ1
= 1−2i;λ2
= 1 + 2ix
(C1
cos 2x+C2
sin 2x)