TM NGHI^E.M T^O'NG QUAT CU'A PHU.O.NG TRNH X2Y”−2XY0−4Y= 0,KHI BI...
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Tm nghi^e.m t^o'ng quat cu'a phu.o.ng trnh
x2
y”−2xy0
−4y= 0,khi bi^et m^o.t nghi^e.m ri^eng co da.ng
y1
= 1x.
HD gia’i: y1
= 1xla m^o.t nghi^e.m cu'a phu.o.ng trnh. Ta tm nghi^e.m ri^eng
y2
=u(x)1x.Thay vao phu.o.ng trnh ta tm du.o..c
y2
=x4
.V^a.y nghi^e.m t^o'ng quat cu'a phu.o.ng trnh
la
y= C1
x +C2
x4
.