A) 2X 3 X 1 X 2 X 2B) X2 – 4X ≤ 5 ⇔ (X – 2)2 ≤ 33 ⇔ | X – 2 | ≤ 3...
11. a)
2x 3 x 1
x 2
x 2
b) x
2
– 4x ≤ 5 ⇔ (x – 2)
2
≤ 3
3
⇔ | x – 2 | ≤ 3 ⇔ -3 ≤ x – 2 ≤ 3 ⇔ -1 ≤ x ≤ 5.
c) 2x(2x – 1) ≤ 2x – 1 ⇔ (2x – 1)
2
≤ 0. Nhưng (2x – 1)
2
≥ 0, nên chỉ cĩ thể : 2x – 1 = 0
Vậy : x = ½ .