KHẢO SÁT Y X = 4− 6X2+ 5 . MXĐ

1/ Khảo sát y x =

⁴

− 6x

²

+ 5 . MXĐ: D=R

( )

y' 4x 12x 4x x 3 ,y' 0 x 0 hayx 3

=

³

− =

²

− = ⇔ = = ±

y'' 12x =

2

− 12,y'' 0 = ⇔ = ± x 1

BBT x −∞ − 3 ^{-1 0 1} 3 +∞

y' _{- 0 + + 0 - - 0 +}

y'' _{+ + 0 - - 0 + +}

y +∞ 5 +∞

-4 0 0 -4

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