GIA'I PHU.O.NG TRNH

118)

Gia'i phu.o.ng trnh:

y” + 2y

0

+y= sinx+ e

−x

xHD gia’i:

Phu.o.ng trnh da.c tru.ng

λ

2

+ 2λ+ 1 = 0λ=−1

(b^o.i 2)

Nghi^e.m t^o'ng quat:

y=e

−x

(C

1

x+C

2

).

Tm nghi^e.m ri^eng da.ng:

y=α

1

(x)xe

−x

+α

2

(x)xe

−x

Bi^en thi^en hang s^o:

α

1

= e

x

α

0

1

=e

x

sinx+ 12(sinx−cosx) + ln|x|⇒α

0

2

=−xe

x

sinx− xα

2

=−[xe

x

22 (sinx−cosx) + e

x

2 cosx]− x

2

4

Suy ra nghi^e.m t^o'ng quat:

y=e

−x

(C

1

x+C

2

) +xe

−x

ln|x| − cos2x x

2

e4

−x

.