MA=(M−1; 4M−2 ;) MB =(M+1; 4M)A, M, B THẲNG HÀNG ⇔MA||MB ⇔4M M( −1) (...

4. - __10_BAI_TOAN_KHAO_SAT_HAM_SO
__10_BAI_TOAN_KHAO_SAT_HAM_SO

4.3. Ta có:

MA=

(

m−1; 4m−2 ;

)

MB =

(

m+1; 4m

)

A, M, B thẳng hàng

⇔MA||MB ⇔4m m

(

−1

) (

= m+1 4

)(

m−2

)

6 2 1⇔ = ⇔ =m m 3

Đáp số:

1m = 3