GIẢI CỎC PHƯƠNG TRỠNH TỚCH SAU

Bài 4: Giải cỏc phương trỡnh tớch sau:

a. (x - 1)(5x + 3) = (3x - 8)(x - 1)

b. 3x(25x + 15) - 35(5x + 3) = 0

c. (2 - 3x)(x + 11) = (3x - 2)(2 - 5x)

d. (2x

2

+ 1)(4x - 3) = (2x

2

+ 1)(x - 12)

e. (2x + 1)

2

+ (2 - x)(2x - 1) = 0

f. (x + 2)(3 - 4x) = x

2

+ 4x + 4

Giải: a. (x - 1)(5x + 3) = (3x - 8)(x - 1)

(x - 1)(5x + 3) - (3x - 8)(x - 1) = 0

(x - 1)(5x + 3 - 3x + 8) = 0

11

(x - 1)(2x + 11) = 0

x = 1 hoặc x = -

2,1 11  2

Vậy S =



15x(5x + 3) - 35(5x + 3) = 0

(5x + 3)(15x - 35) = 0

73

hoặc x =

x = -

53;7 3

(2 - 3x)(x + 11) + (2 - 3x)(2 - 5x) = 0

2 - 3x)(x + 11 + 2 - 5x) = 0

(2 - 3x)(- 4x + 13) = 0

2

hoặc x =

13

x =

4;13

(2x

2

+ 1)(4x - 3) - (2x

2

+ 1)(x - 12) = 0

(2x

2

+ 1)(4x - 3 - x + 12) = 0

(2x

2

+ 1)(3x + 9) = 0

x = - 3

Vậy S =  

3

(2x - 1)(2x - 1 + 2 - x) = 0

(2x - 1)(x + 1) = 0

1

hoặc x = - 1

1 ; 1

(x + 2)(3 - 4x) - (x + 2)

2

= 0

(x + 2)(3 - 4x - x - 2) = 0

(x + 2)(-5x + 1) = 0

x = - 2 hoặc x =

;1 5

Tiết 26: