TM NGHI^E.M RI^ENG CU'A PHU.O.NG TRNH

13)

Tm nghi^e.m ri^eng cu'a phu.o.ng trnh:

^xy

⁰

^=px

²

^−y

²

^+y

thoa' ma~n di^eu ki^e.n d^au

^{y(1) = 0}

.

HD gia’i:rxy

⁰

=px

²

−y

²

+y ⇐⇒ y

⁰

=1− y

²

x

²

+ yx

da.t

^u= _x^y

hay

^y=ux

suy ra

^y

⁰

^=xu

⁰

^+u

phu.o.ng trnh thanh:

^xu

⁰

^=√1−u

²

^{⇐⇒ √ du}1−u

²

= dx⇐⇒ arcsinu= lnCx

thoa' ma~n di^eu ki^e.n d^au

^{y(1) = 0}

khi

^{C = 1}

. V^a.y nghi^e.m

^y=±x

.