1) 2 log
22x − 14 log
4x + = 3 0 ⇔ 2 log
22 x − 7 log
2x + = 3 0
log 1
⇔ log
2 x = 3 hay
2x = 2 ⇔ x = 2
3 = 8 hay x = 2
12 = 2
1 11 1 1 1
x − x + x = − + =
2 2 4 3 2( 1) ( 2 )
I = ∫ x x − dx = ∫ x − x + x dx =
5 4 3 1( )
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