(1,0 ®IÓM) (2,0 ®IÓM) §ÆT U = 1 – X3 ⇒ DU = -3X2DX. VÍI X = -1 ⇒...

1. (1,0 ®iÓm)

(2,0 ®iÓm)

§Æt u = 1 – x

3

du = -3x

2

dx. Víi x = -1

u = 2, x = 1

u = 0.

0,50

1

1

1

2

32

= −

0

4

=

2

4

=

5

=

I

(

u )du

u du

u

0,50

3

3

15

0

5

.

2

0