(1,0 ®IÓM) (2,0 ®IÓM) §ÆT U = 1 – X3 ⇒ DU = -3X2DX. VÍI X = -1 ⇒...
1. (1,0 ®iÓm)
(2,0 ®iÓm)
§Æt u = 1 – x
3
⇒du = -3x
2
dx. Víi x = -1
⇒u = 2, x = 1
⇒u = 0.
0,50
1
1
1
2
32
= −
∫
0
4
=
∫
2
4
=
5
=
I
(
u )du
u du
u
0,50
3
3
15
0
5
.
2
0