(1,0 ®IÓM) XÐT TRªN ®O¹N [0; 2], HΜM SÈ ®· CHO CÃ
2. (1,0 ®iÓm)
XÐt trªn ®o¹n [0; 2], hµm sè ®· cho cã:
f′(x)=4x3
−4x=4x(x2
−1);
0,50
⎡
⇔
=
0
0
x
′
=
f
(
x
)
⎢
⎣
=
1
f(0) = 1; f(1) = 0; f(2) = 9.
min f(x)=0,
max f(x)=9.
0,50
VËy
[0;2]
2. (1,0 ®iÓm)
XÐt trªn ®o¹n [0; 2], hµm sè ®· cho cã:
f′(x)=4x3
−4x=4x(x2
−1);
0,50
⎡
⇔
=
0
0
x
′
=
f
(
x
)
⎢
⎣
=
1
f(0) = 1; f(1) = 0; f(2) = 9.
min f(x)=0,
max f(x)=9.
0,50
VËy
[0;2]