2.LOG5135 = 3 A= 12LOG2(3.25) LOG23 = 2B−23A A= 12LOG23 + LOG25 A= LOG...

2

.log

5

135 =

3

a

=

1

2

log

2

(3.25)

log

2

3 = 2b

2

3

a

a

=

1

2

log

2

3 + log

2

5

a

= log

4

75

Lại có:

b

= log

8

45

b

=

1

3

log

2

(9.5)

b

=

2

3

log

2

3 +

1

3

log

2

5

log

2

5 =

4

3

a

b

.

3 2b

2

3

a

+

4

3

a

b

Do đó:

log

3

25

135 =

3

4

2