2Z[4F (X) − 2X]DX = 11⇔ 4F (X)DX − 2XDX = 1F (X)DX − 2 · X221 = 1F (X)DX = 4⇔F(X)DX = 1

Câu 33. Ta có:

2

Z

[4f (x) − 2x]dx = 1

1

⇔ 4

f (x)dx − 2

xdx = 1

f (x)dx − 2 · x

2

2

1

= 1

f (x)dx = 4

f(x)dx = 1.

Chọn đáp án A