2) ∀ M ∈ d : M(m; 5 61
=
BCNMAB 48
4 24
5
Phửụng trỡnh tieỏp tuyeỏn cuỷa ( C) taùi M
0(x0;y
0 ):
V = V
Thoỷa YCBT :
.0,25
S BCNM 4
BCNMAB
3 2x x
2 7
y x = ( - x
02- x
0+ 2 )(x
− − − + + ữ ữ
0 09 108 128 0
2 2x ax a
⇔ − + =
3 2 3
0x = 4a (Nhaọn)
– x
0 )
3
Tieỏp tuyeỏn ủi quaM ⇔
⇔
x = 32a (Loaùi)
m x = (
5 61 2 7
+ − − − + + ữ ữ
4 24 3 2 3
KL : x = 4a
2- - + )(m – x
0 )
0 0 2
x m x mx m
2 1 3 5 0
Caõu VIa : ( 2 ủieồm )
+ − ữ − + − =
3 2 4 24
0 0 0
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