TM NGHI^E.M RI^ENG CU'A PHU.O.NG TRNH
51)
Tm nghi^e.m ri^eng cu'a phu.o.ng trnh:
yey
=y0
(y3
+ 2xey
)thoa' ma~n di^eu ki^e.n d^au
y(0) =−1.
HD gia’i:Xem
xla ^a'n ham, thay
y0
= 1x0
, phu.o.ng trnh thanh
x0
− 2yx = y2
e−y
.
NTQ cu'a phu.o.ng trnh tuy^en tnh thu^an nh^at tu.o.ng u.ng la
x = Cy; bi^en thi^en hang
s^o du.o..c
C(y) =−e−y
+C. Nhu. v^a.y NTQ la
x= Cy −ye1y