14 32222 X XX XLIM 1XLIM 14 2* 0X1()LIMX...

1 )1

4

3

2

 xx xlim 1

4

2

* 0()lim

x



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x x x x)(* BBT x 0 + f’(x) f(x) 1 0 Vậy: 0 < m 1Câu VI a. tx 3 2