= +  Y X XB/ 2 13 SIN3− +2X 5X 3SXA LIM= + −X 1 23X X 4→...

Câu 7 :

=

+

y

x

x

b/

2

1

3

sin

3

+

2x

5x 3

S

x

A lim

=

+ −

x 1

2

3x

x 4

'

6

1

.sin

(

)

( )

=

2

+

x 1 2x

2x 3

0,25

lim

x 1 3x 4

=

+

(

)(

)

x 1

K

3

1

.cos

+

+

x

x

D

A

2x

2x 3

+

lim

3x 4

=

+

1

I

H

O

=

---

7

M

B

C

=

=

+