 + + =2 0 (*)X AX B+ + + + = ⇔  + + =2 2( )( ) 0X AX B X BX A 2X BX...

Câu 2 :

a)

P= cos

2

α 2 1 sin

2

α + =1 cos

2

α2 cos

2

α +1cos

2

2cos 1P=

α

α

+

(vì cosα > 0)

(cos 1)

2

P=

α

−1 cosP= −

α (vì cosα < 1)

b) (

4+ 15

)(

5 3

)

4 15 =

(

5 3

) (

4+ 15

) (

2

4 15

) = (

5 3

)

4+ 15

= (

5 3

) (

2

4+ 15

) = (

8 2 15 4

)(

+ 15

) =

2