1-6
(a)
F y = − F − f N cos θ + N sin θ = 0 (1)
y F x = f N sin θ + N cos θ − T
Fr = 0
TF = N (sin θ − f cos θ ) Ans .
xrT = N r ( f sin θ + cos θ )
Nf NCombining
T = Fr 1 + f tan θ
tan θ − f = KFr Ans . (2)
(b) If T → ∞ detent self-locking tan θ − f = 0 ∴ θ cr = tan − 1 f Ans .
(Friction is fully developed.)
Check: If F = 10 lbf, f = 0.20, θ = 45 ◦ , r = 2 in
N = 10
− 0 . 20 cos 45 ◦ + sin 45 ◦ = 17 . 68 lbf
T
r = 17 . 28(0 . 20 sin 45 ◦ + cos 45 ◦ ) = 15 lbf
f N = 0 . 20(17 . 28) = 3 . 54 lbf
θ cr = tan − 1 f = tan − 1 (0 . 20) = 11 . 31 ◦
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