1-8
Given, F = 10 + 2 . 5x lbf, r = 2 in, h = 0 . 2 in, θ = 60 ◦ , f = 0 . 25, x i = 0, x f = 0 . 2
F i = 10 lbf ; F f = 10 + 2 . 5(0 . 2) = 10 . 5 lbf Ans.
From Eq. (1) of Prob. 1-6
N = F
− f cos θ + sin θ
N i = 10
− 0 . 25 cos 60 ◦ + sin 60 ◦ = 13 . 49 lbf Ans.
N f = 10 . 5
10 13 . 49 = 14 . 17 lbf Ans .
From Eq. (2) of Prob. 1-6
K = 1 + f tan θ
tan θ − f = 1 + 0 . 25 tan 60 ◦
tan 60 ◦ − 0 . 25 = 0 . 967 Ans.
T
i = 0.967(10)(2) = 19.33 lbf · in
T
f= 0.967(10.5)(2) = 20.31 lbf · in
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