2LOG22X − 14LOG4X + = 3 0 ⇔ 2LOG22X − 7 LOG2 X + = 3 0LOG 1⇔ LOG2X = 3 HAY 2X = 2 ⇔ X = 23 = 8 HAY X = 212 = 21 11 1 1 1X − X + X = − + =2 2 4 3 2I = ∫ X X − DX = ∫ X − X + X DX = 5 4 3 1( ( 2 )( )
1) 2log
2
2
x − 14log
4
x + = 3 0 ⇔ 2log
2
2
x − 7 log
2
x + = 3 0
log 1
⇔ log
2
x = 3 hay
2
x = 2 ⇔ x = 2
3
= 8 hay x = 2
1
2
= 2
1
1
1 1 1 1
x − x + x = − + =
2
2
4
3
2
I = ∫ x x − dx = ∫ x − x + x dx =
5
4
3
1