GIA'I H^E. PHU.O.NG TRNH
184)
Gia'i h^e. phu.o.ng trnh:
dydt + 3x+y= 05−λ 3= 0⇔λ= 2(b^o.i 2)
HD gia’i:Phu.o.ng trnh da.c tru.ng
−3 −λ−1a−3b= 3d⇒nghi^e.m co da.ng
atct++dbe2t
thay vao h^e.
⇒a+c= 0c+ 3b =−3dCho
a =C1
, b=C2
⇒c=−C1
, d= C1
3 −C2
x= (C1
t+C2
)e2t
V^a.y nghi^e.m t^o'ng quat:
y= (−C1
t+C1
3 −C2
)e2t
.dxdt = 2x−3y