GIA'I H^E. PHU.O.NG TRNH

184)

Gia'i h^e. phu.o.ng trnh:

dydt + 3x+y= 05−λ 3= 0⇔λ= 2

(b^o.i 2)

HD gia’i:

Phu.o.ng trnh da.c tru.ng

−3 −λ−1a−3b= 3d⇒

nghi^e.m co da.ng

atct++dbe

2t

thay vao h^e.

a+c= 0c+ 3b =−3d

Cho

a =C

1

, b=C

2

⇒c=−C

1

, d= C

1

3 −C

2

x= (C

1

t+C

2

)e

2t

V^a.y nghi^e.m t^o'ng quat:

y= (−C

1

t+C

1

3 −C

2

)e

2t

.dxdt = 2x−3y