GIA'I PHU.O.NG TRNH

82)

Gia'i phu.o.ng trnh:

^(ycos

²

^{x−sinx)dy=ycosx(ysinx+ 1)dx}HD gia’i: ∂P∂y = ∂Q∂x =ysin 2x+ cosx

NTQ:

x

y

RP(x, y

₀

)dx+Q(x, y)dy=C ⇔ysinx− y

²

2 cos

²

x=C

x

0

=0

y

0

=0