BÀI 3. (2 ĐIỂM) TÌM X BIẾT A) 6X2 – 2 – 3 3( X )( X+2)=1B) (X+1 –) (...
1. = −xb) (x+1)
3
−(x−1)(x2
+ + − =x 1) 2 0 + − − − =3
3
(x 1) (x 1) 2 0 + + + − + − =3
2
3
3 3 1 1 2 0x x x x + = 3 (x x 1) 0 =0x = − 13
−(x−1)(x2
+ + − =x 1) 2 0 + − − − =3
3
(x 1) (x 1) 2 0 + + + − + − =3
2
3
3 3 1 1 2 0x x x x + = 3 (x x 1) 0 =0x = − 1