00HCL (K) + AQ → H + (AQ) + CL - (AQ) ∆ H O 3 = − 75 , 13 KJ/MOL (3)...

1, - DAP AN - NO
DAP AN - NO

1,00

HCl (k) + aq → H + (aq) + Cl - (aq) ∆ H o 3 = − 75 , 13 kJ/mol (3)

Lấy (1) - (2) + (3) ta có:

1 Cl 2 (k) + aq + e → Cl - (aq) ∆ H o x kJ/mol

2

=

+

−

∆ H o x ( 92 , 2 kJ / mol ) ( 0 kJ / mol ) ( 75 , 13 kJ / mol ) -167,33 kJ/mol