LN I = LIM→ LN(2010 + )PQR=O LIM→ 2010 LN 2010 + 12010 + =O2010 LN 2010 + 1PQR LIM→ 2010 LN 2010=O2010 LN 2010 = LN 2010PQR LIM→ 2010 LN(2010V Ậ Y I = 2010
Câu 1. Ta có:
ln I = lim
→
ln(2010 + )
PQR
=O lim
→
2010 ln 2010 + 1
2010 + =O
2010 ln 2010 + 1
PQR
lim
→
2010 ln 2010
=O
2010 ln 2010 = ln 2010
PQR
lim
→
2010 ln
(