CÂU 50. TA CÓΠΠZ2Z2Π 22 SIN2X − Π= Π − 2DX =(1 − SIN 2X) DX =X + COS 2...

2 .

2

4

0

18

Dẫn tới

π

Z

2

h

i

f

2

(x) − 2 √

2f(x) sin

+ 2 sin

2

x − π

dx = 0

i

2

f (x) − √

2 sin

dx = 0.

Hay ta có

2

f(x) dx =

dx = − √

2 cos

0

= 0.