+ = ⇔ = −0B C B C⇔ − − + = −23 33 7 2008 6 2009X X X(3 7 2008) 6 2009 = +1 13X3 1 0 6⇔ − − = ⇔X X = −6
2)
+ = ⇔ = −
0
b c
b
c
⇔ −
−
+
=
−
2
3
3
3
7
2008
6
2009
x
x
x
(3
7
2008) 6
2009
=
+
1
13
x
3
1 0
6
⇔
− − = ⇔
x
x
=
−
6