A⇔  = Π − + ΠΠ(1,5Đ’)Π 2X K26SIN2X = SIN62X K26 = + ΠΠ0.75Đ’X...

Toán DE THI THU TOAN 11 KHI MOI CO DAP AN VA THANG DIEM

1.a⇔  = π − + ππ(1,5đ’)π 2x k26sin2x = sin2x k2 = + ππ0.75đ’x k ∈12 k Z πx 5 k = + π12