2 21 0 1 5 5          X X X XCÓ   2 2 4 4   2 2 21...

Bài 6:

2

2

1

0

1

5 5

  

  

x

x

x

x

2

2

4 4

2

2

2

1

5

5

25

A

x

 

 

x

2

4

4

16

 

Dấu “=” xảy ra

1

 

x

2

A

 

x

Vậy min

25

1

16

2