A) X3+ (1−X2)3 =X 2 1( −X2)B) ( )3 ( )32 21+ 1−X 1−X − 1+X = +2 1−XC) 1− −X 2X 1−X2 −2X2+ =1 0D) 64X6−112X4+56X2− =7 2 1−X2X XE) 2 351 12−+ X =F) (X−3) (X+ +1) (4 X−3) XX−+13 = −3
Bài 2: Giải phương trỡnh:a) x
3
+(
1−x2
)
3
=x 2 1(
−x2
)
b)( )
3
( )
3
2
2
1+ 1−x 1−x − 1+x = +2 1−xc) 1− −x 2x 1−x2
−2x2
+ =1 0d) 64x6
−112x4
+56x2
− =7 2 1−x2
x xe)2
351 12−+ x =f)