 HCOOH HCOONA    CH COOH CH COONA H OTA CÓ

Câu 14.

 

HCOOH HCOONa

   



 

CH COOH CH COONa H O

Ta có:

₃

^NaOH

₃

₂

; n

NaOH

 0,04mol  n

H O

2

 0,04mol

 

C H OH C H ONa

 

6

5

6

5

m

Mu i khan

 2,46 0,04.40 0,04.18 3,34gam   

ă ápăánăB