2 = 75 (CÂU C). H = 17 CH CHO H 3 + 2 → XT T0 CH CH OH 3 2XT2 2...

43, 2 = 75

(câu c).

H =

17 CH CHO H 3 + 2 → xt t

0

CH CH OH 3 2

xt

2 2

0

3 2

CH = CH COOH H − + → t CHCHCOOH

CH = CH COOH NaOH − +  → CH = CH COONa H O − +

2 2 2

CH = CH COOH NaCO − +  → CH = CH COONa CO − + + H O

2 3 2 2 2

NaHCO + NaOH  → Na CO + H O

3 2 3 2

Có 5 phản ứng xảy ra (câu a).