{ }= = 0P C120( )=X0 515504C201 4C C* 25= = 15 5P C( )=X1 55...

39.

{ }

= = 

0

P C1

20

(

)

=

x

0

5

15504C

1

4

C C* 25= = 

15

5

1

5

5168

2

3

* 175

2

5

==>2584

3

2

* 2275

3

5

7752

4

1

4

5

5

0

* 1001

5

5

=

=

1

P

C

15504

C

*

25

C

C

=

=

5168

*

175

=

=

==>

2584

*

2275

=

=

7752

*

1001

X 0 1 2 3 4 5P 12517522751001