.( )2 23 3 2 3 3 15 12 0X X X X X2 ≥3X X⇔ ⇔ =2 4 = ∨ =X X1 4
Câu 2:
.
( )
2
2
3
3
2
3
3
15
12 0
x
x
x
x
x
2
≥
3
x
x
⇔
⇔ =
2
4
= ∨ =
1
4
Câu 2:
.
2
2
3
3
2
3
3
15
12 0
x
x
x
x
x
2
≥
3
x
x
⇔
⇔ =
2
4
= ∨ =
1
4