.( )2 23 3 2 3 3 15 12 0X X X X X2 ≥3X X⇔ ⇔ =2 4 = ∨ =X X1 4

Câu 2:

.

( )

2

2

3

3

2

3

3

15

12 0

x

x

x

x

x

2

 ≥

3

x

x

⇔ =

2

4

 = ∨ =

1

4