A) P = 2 A A 1 7 A 3   A 3 A 3 ( A 3)( A 3) 3A437AAAA...

Câu 2:a) P = 2 a a 1 7 a 3   a 3 a 3 ( a 3)( a 3) 3a4726))(1(= ( 3)( 3)9= 3 Vậy P = 3 aa 3 .b) P < 1  3 a 3 91 3 a a 3 a 0 a .2 4a 3        