C X 1  6 C X 2  6 C X 3  9 X 2  14 X 2) 3 2 1AX A P2 X  X  C X A X2

1) C x 1  6 C x 2  6 C x 3  9 x 2  14 x 2) 3 2 1

A

x A P

2 xxC x

A x

2