11.13 The ROM cell is smaller than the SRAM cell. It presents one unit of capacitance
for the transistor. Assume the wire capacitance is 1/2 as much, so each cell pre-
sents 1.5C on the wordline. It has only a single transistor in the pulldown path on
the bitline so the resistance is R. Hence, the logical effort is 1/2, as compared to 2
for the SRAM cell.
The bitline has a capacitance of C/2 from the half contact. If the wire capacitance
is again C/2, the total bitline capacitance is 2
n C. Because the cell has a resistance
R, the delay is 2
n RC and the parasitic delay is 2
n/3.
The ROM can use the same decoder as the SRAM, with a logical effort of (n+2)/3
and parasitic delay of n. Assume the bitline drives a load equal to that seen by the
address so the path electrical effort is H = 1.
Putting this all together, the path effort is F = GBH = 2
N(n+2)/6. The path para-
sitic delay is n + 2
n/3. The path delay is D = 2N + 4log
4[(n+2)/6] + n + 2
n/3.
Your modeling and loading assumptions may vary somewhat. The assumptions
about wire capacitance have a large effect on the model.
Chapter 12
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