X   1 X  9, 6  X  Y  0, 6    HPU2  0, 4Y XTR NG H P 1

Câu 11:

M n

cho n m n n

:

_X

  1

_X

 9, 6 

^X



^Y

 0, 6   

_H

^pu

2

 0, 4

Y

X

Tr ng h p 1: N u A là anken :

  

   

n 0, 4 mol 9, 6 0, 4.2

 

H

2

X M 14, 67

A



n 0, 6 mol 0, 6 (lo i)

Anken

Tr ng h p 2: N u A là ankin:

n 0,8 mol 9, 6 0,8.2

 

X M 40 C H

A

3

4

n 0, 2 mol 0, 2

áp án : A