A) P = 2 A A 1 7 A 3 A 3 A 3 ( A 3)( A 3)   =)(37)3)1(3(2AAAAA26...

Câu 2: a) P = ^{2 a a 1 7 a 3}

 

a 3 a 3 ( a 3)( a 3)

   

=

)(

3

7

)

1

(

2

a

6

4





 

9

= 3

 

Vậy P = ^{3 a}

a 3  .

b) P < 1  3 a 1 3 a a 3 a 3 0 a 9

2 4

a 3         

 .