[(A – B)2 + (B – C)2 + (C – A)2] = A B B C C A 1 A
2
.(a + b + c).[(a – b)2
+ (b – c)2
+ (c – a)2
] =a b
b c
c a
1
a
. 1
b
. 1
c
.
.
b
c
a
=
2
.(a + b + c).[(a – b)2
+ (b – c)2
+ (c – a)2
] =a b
b c
c a
1
a
. 1
b
. 1
c
.
.
b
c
a
=