BPT ⇔ 0 < X2 3X 2X X⇔ 2− 2≤ <X 1 HAY 2 X 2 2 2< ≤ +NA/= =...

1. Bpt ⇔ 0 < x

2

3x 2x x⇔ 2− 2≤ <x 1 hay 2 x 2 2 2< ≤ +NA

/

= = (đvtt)