1900 58-58-12 - TRANG | 18 - NCUSO4 = 0,02 MOL     DPDD2CUSO 2H O 2CU 2H SO O4 2 2 4 2   0, 02(MOL) 0, 02(MOL) 0, 02(MOL) 0, 01(MOL) M 0, 02*64 1, 28(GAM)CUV 0, 01* 22, 4 0, 224(LIT)O2ÁP ÁN

câu 35: - BAI 2 DAP AN CAC DANG BAI DIEN PHAN N2 câu 35: - BAI 2 DAP AN CAC DANG BAI DIEN PHAN N2
BAI 2 DAP AN CAC DANG BAI DIEN PHAN N2

Câu 35:

T ng đài t v n: 1900 58-58-12 - Trang | 18 -

nCuSO

4

= 0,02 mol

    

dpdd

2CuSO 2H O 2Cu 2H SO O

4

2

2

4

2

   

0, 02(mol) 0, 02(mol) 0, 02(mol) 0, 01(mol)

 

m 0, 02*64 1, 28(gam)

Cu

V 0, 01* 22, 4 0, 224(lit)

O

2

áp án : A